(H-3/4)^2=7/16

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Solution for (H-3/4)^2=7/16 equation: 


H in (-oo:+oo)

(H-(3/4))^2 = 7/16 // - 7/16

(H-(3/4))^2-(7/16) = 0

(H-3/4)^2-7/16 = 0

(16*(H-3/4)^2)/16-7/16 = 0

16*(H-3/4)^2-7 = 0

16*H^2-24*H+2 = 0

16*H^2-24*H+2 = 0

2*(8*H^2-12*H+1) = 0

8*H^2-12*H+1 = 0

DELTA = (-12)^2-(1*4*8)

DELTA = 112

DELTA > 0

H = (112^(1/2)+12)/(2*8) or H = (12-112^(1/2))/(2*8)

H = (4*7^(1/2)+12)/16 or H = (12-4*7^(1/2))/16

2*(H-((12-4*7^(1/2))/16))*(H-((4*7^(1/2)+12)/16)) = 0

(2*(H-((12-4*7^(1/2))/16))*(H-((4*7^(1/2)+12)/16)))/16 = 0

(2*(H-((12-4*7^(1/2))/16))*(H-((4*7^(1/2)+12)/16)))/16 = 0 // * 16

2*(H-((12-4*7^(1/2))/16))*(H-((4*7^(1/2)+12)/16)) = 0

( 2 )

2 = 0

H belongs to the empty set

( H-((12-4*7^(1/2))/16) )

H-((12-4*7^(1/2))/16) = 0 // + (12-4*7^(1/2))/16

H = (12-4*7^(1/2))/16

( H-((4*7^(1/2)+12)/16) )

H-((4*7^(1/2)+12)/16) = 0 // + (4*7^(1/2)+12)/16

H = (4*7^(1/2)+12)/16

H in { (12-4*7^(1/2))/16, (4*7^(1/2)+12)/16 }

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